A helium sample occupies 1.50 L of space at 124.6 kPa. What pressure would the helium need to experience to have a volume of 0.75 L?

A. 130 kPa
B. 97 kPa
C. 250 kPa
D. 62 kPa

Answer : The correct option is, (C) 250 kPa

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

or,

where,

= initial pressure = 124.6 kPa

= final pressure = ?

= initial volume = 1.50 L

= final volume = 0.75 L

Now put all the given values in the above equation, we get:

Thus, the pressure of helium need to experience to have a volume of 0.75 L would be, 250 kPa

answer; i believe that the correct answer is (a) potassium(k)

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3