For the reaction Ag2S(s) ⇌ 2Ag+(aq) + S2−(aq), what happens to the equilibrium position if the amount of silver ion is halved?For the reaction S(s) ⇌ 2(aq) + (aq), what happens to the equilibrium position if the amount of silver ion is halved?

More silver and sulfide ions will be yielded as the reaction proceeds.

Explanation:

Hello,

In this case, with the given reaction at equilibrium:

We take into account the Le Chatelier's principle in order to explain what would happen when the amount of solver ion is halved. Thus, it explains that when the amount of one product is diminished as in this case, since by halving its amount is reduced to the half, the direct reaction is favored (reaction will shift rightwards), it means the formation of products, so more silver and sulfide ions will be yielded as the reaction proceeds.

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the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation:

away from the curb

explanation:

the wheels would then hit the curb if it started to rolling, decreasing the chance of an accident.