The volume of a gas collected when the temperature is 11.0 degC and the pressure is 0.934 atm measures 0.0148 L. What is the calculated volume of the gas at 20.0 degC and 0.974 atm?

0.0146cm^3

Explanation:

Using the combined Gas Law P1V1/t1 = P2V2 /t2

P1.. 0.934

V1..0.0148

T1..11° ( 284K)

P2 =0.974

V2= V2 (unknown)

T2= 20° (293K)

Hence 0.934x 0.0148 / 284 = 0.974x V2 / 293

0.000048= 0.974V2 /293

0.000048 x 293 = 0.974V2

0.01426=0.974V2

V2 = 0.01426/ 0.974

V2 = 0.0146 cm^3

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.