Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH(aq). Calculate the amount of Ga(s) that can be deposited from a Ga(III) solution using a current of 0.590 A that flows for 30.0 min.

0.256 g

Explanation:

The deposition of Ga from Ga(III) solution

According to mole concept:

1 mole of an atom contains number of particles.

We know that:

Charge on 1 electron =

Charge on 1 mole of electrons =

where,

I = current passed = 0.590 A

q = total charge = ?

t = time required = 30.0 min = 1800 s (1min=60s)

Putting values in above equation, we get:

will deposit = 70 g of Gallium

will deposit = of Gallium

Thus 0.256 g of Ga(s) that can be deposited from a Ga(III) solution using a current of 0.590 A that flows for 30.0 min.

answer; /// i do believe that the correct answer is (c)nuclear bond