How many atoms of phosphorus are in 2.30 mol of copper(ii) phosphate? i'm having trouble figuring out the steps. i do know avogadro's number is needed! 6.022x10^23

Answer is 2.77012 x 10²⁴

Explanation;

The formula of copper(II) phosphate is Cu₃(PO₄)₂. Hence, 1 Cu₃(PO₄)₂ has 2 P atoms. The stoichiometric ratio between Cu₃(PO₄)₂ and P atom is 1 : 2.

Hence,

moles of P atoms = moles of Cu₃(PO₄)₂ x 2

= 2.30 mol x 2 = 4.60 mol

According to the Avogadro's constant, 1 mole has 6.022 x 10²³ particles.

Hence, number of P atoms = Avogadro's constant x number of moles

= 6.022 x 10²³ mol⁻¹ x 4.60 mol

= 2.77012 x 10²⁴

58750.08068 is the answer i think

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the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).