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Calculate the volume of 1.5 M nitric acid required to neutralize 30.0 mL of 7.0 M sodium hydroxide.

.14L or 140mL

Explanation:

This is a classic plug-n-chug problem. Your textbook probably goes over this formula as . M stands for molarity of the given substance, and V stands for the volume that the substance occupies.

Simply plug in the values that you're given, like so:

After completing the algebra portion and solving for the unknown, you will be left with x = .14L, which is the volume required to neutralize 30mL of 7M NaOH.

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it's c. elements are placed in rows based on how may valencies electrons have.