A gas of 3.4 moles occupies a volume of 0.046 L at 298 K. What is the pressure in kPa?
a. 6.1 x 10^2 kPa
b. 9.45 x 10^-3 kPa
c. 4.40 x 10^5 kPa
d. 2.1 x 10^5kPa

Answer : The correct option is,

Explanation :

To calculate the pressure of gas we are using ideal gas equation as:

where,

P = pressure of gas = ?

V = volume of gas = 0.046 L

n = number of moles of gas = 3.4

R = gas constant = 8.314 L.kPa/mol.K

T = temperature of gas = 298 K

Now put all the given values in the above formula, we get:

Therefore, the pressure of gas is,

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.