What is the coefficient in front of the sulfuric acid when it reacts with aluminum hydroxide in a balanced neutralization reaction?
A.1
B.2
C.3
D.4

C.3

Explanation:

The coefficient is the number of molecules needed for a set of reactions. The different reactions will have a different coefficient, so you have to balance the reaction first by knowing all the reactants and the product the reaction. The balanced reaction for sulfuric acid and aluminum hydroxide is:

2 Al(OH)3(s) + 3 H2SO4(aq) > Al2 (SO4)3(aq) + 6 H2O(l)

Every set of reactions will need 3 molecules of sulfuric acid and 2 molecules of aluminum hydroxide. The coefficient in front of sulfuric acid (H2SO4) is 3.

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solid ice forms on leaves.

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answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole