A 10 gram iron nail absorbed 125J of heat. What was the final temperature of the nail if the original temperature was 25°C?

52.1 degrees C

Explanation:

We need to use the equation: q = mCΔT, where m is the mass in grams, C is the specific heat capacity, and ΔT is the change in temperature.

Here, m = 10 g and q = 125 J. The heat capacity of iron is about 0.461 J/(g * C). And, our initial temperature is 25. So:

125 J = (10 g) * (0.461 J/(g * C)) * (T_f - 25)

Solving for T_f (final temp), we get: 52.1 degrees C

Hope this helps!

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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