2. Let us say we have a birthday's balloon filled with a volume of 8 liters of 25 points

Helium gas and we measure its pressure to be 0.8 atm. Then after, I've

decided to squeeze it to reduce its volume (size) to 0.5 liters (which

about to pop!), what is the balloon's new pressure?

A.12.8 atm

B.12.0atm

C.10.8 atm

D.11.8 atm

Option A.12.8 atm

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 8 L

Initial pressure (P1) = 0.8 atm

Final volume (V2) = 0.5 L

Final pressure (P2) =?

Step 2:

Determination of the new pressure. The new pressure of the balloon can simply be obtained by applying the Boyle's law equation as follow:

P1V1 = P2V2

0.8 x 8 = P2 x 0.5

Divide both side by 0.5

P2 = (0.8 x 8) / 0.5

P2 = 12.8 atm

Therefore, the new pressure of the balloon is 12.8 atm

h

the correct answer is:

a. formation of precipitation