30.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 37.85 mL of a 0.1361 M NaOH solution. What is the concentration of the H2SO4 solution

The concentration of the H2SO4 solution is 0.0858 M

Explanation:

Step 1: Data given

Volume of H2SO4 = 30.00 mL = 0.030 L

Volume of NaOH= 37.85 mL = 0.03785 L

Concentration of NaOH= 0.1361 M

Step 2: The balanced equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Step 3: Calculate the concentration of the H2SO4 solution

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 2

⇒with Ca = the concentration of H2SO4 = TO BE DETERMINED

⇒with Va = the volume of H2SO4= 30.0 mL = 0.030 L

⇒with a = the coefficient of H2SO4 = 1

⇒with Cb = the concentration of NaOH = 0.1361 M

⇒with Vb = the volume of NaOH = 37.85 mL = 0.03785 L

2*Ca*0.030 = 1* 0.1361 * 0.03785

0.060 * Ca = 0.00515

Ca = 0.0858 M

The concentration of the H2SO4 solution is 0.0858 M

its first and third is your answer i did the qustion the fourth isnt right

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.