What is the molality of 49 grams of NaCl in 469 grams of H2O (water)

Answer : The molality of sodium chloride is, 1.79 m

Explanation :

To calculate the molality of solution, we use the equation:

Where,

= Given mass of solute (sodium chloride) = 49 g

= Molar mass of solute (sodium chloride) = 58.5 g/mol

= Mass of solvent (water) = 469 g

Now put all the given values in above equation, we get:

Hence, the molality of sodium chloride is, 1.79 m

the millers tale is the answer.

2b2t

explanation:

2b2t