Please help! The Michael reaction is a conjugate addition reaction between a stable nucleophilic enolate ion (the donor) and an α,β-unsaturated carbonyl compound (the acceptor). 1.) Draw the structure of the product of the Michael reaction between ethyl propenoate and 3-oxobutanenitrile.2.)The Michael reaction is a conjugate addition reaction between a stable nucleophilic enolate ion (the donor) and an α,β-unsaturated carbonyl compound (the acceptor). Draw the structure of the product of the Michael reaction between propenamide and 2,4-pentanedione.

See explaination andd attachment

Explanation:

Treatment of aldehydes and ketones with a suitable base can lead to the formation of a nucleophilic species called an enolate that reacts with electrophiles. These C nucleophiles are useful for making new carbon-carbon bonds.

Please kindly see attachment for the drawings.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2