How many mL of 1.01 M LiNO3 solution has 6.63 g of solute?

The answer to your question is 97 ml

Explanation:

Data

volume = ? ml

concentration = 1.01 M LiNO₃

mass = 6.63 g

Process

1.- Calculate the molecular weight of LiNO₃

LiNO₃ = (1 x 6.94) + (1 x 14) + (16 x 3)

          = 6.94 + 14 + 48

          = 69 g

2.- Calculate the moles of LiNO₃

                  69 g 1 mol

                  6.63 g  x

                    x = (6.63 x 1) / 69

                    x = 0.096 moles

3.- Calculate the volume

Molarity = moles / volume

-Solve for volume

Volume = Molarity x moles

-Substitution

Volume = 1.01 x 0.096

-Result

Volume = 0.097 l or 97 ml

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