A gas at 155 Kpa and 25 degrees celsius has a volume of 1 L. The pressure increases to 605 kPa as the temperature is raised to 125 degrees Celsius what is the new volume?

The answer to your question is V2 = 0.34 l

Explanation:

Data

Pressure 1 = P1 = 155 kPa

Temperature 1 = T1 = 25°C = 298°K

Volume 1 = V1 = 1 l

Pressure 2 = P2 = 605 kPa

Temperature 2 = T2 = 125°C = 398°K

Volume 2 = V2 = ?

Process

To solve this problem use the Combined gas law.

           P1V1/T1 = P2V2/T2

-Solve for V2

          V2 = P1V1T2 / T1P2

-Substitution

          V2 = (155)(1)(398) / (298)(605)

-Simplification

          V2 = 61690 / 180290

-Result

          V2 = 0.34 l

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