Write the names of the following ionic compounds: 1) NaOH 2) Co 3 P 2 3) Pb(CO 3 ) 2 4) MgF 2 5) Li 2 SO 3 6) (NH 4 ) 3 PO 4 7) FeO 8) CaSO 4 9) Ag 3 N 10) Na 2 S

1. NaOH is sodium hydroxide

2. Co3P2 is cobalt (II) phosphide

3. Pb(CO3)2 is lead(iv) carbonate or lead(iv) trioxocarbonate(iv)

4. MgF2 is magnesium fluoride

5. Li2SO3 is lithium sulphite

6. (NH4)3PO4 is ammonium phosphate.

7. FeO is iron(II) oxide

8. CaSO4 is calsium sulphate

9. Ag3N is called silver nitride

10. Na2S is sodium sulfide

Explanation:

Step 1:

Data obtained from the question. This includes:

NaOH

Co3P2

Pb(CO3)2

MgF2

Li2SO3

(NH4)3PO4

FeO

CaSO4

Ag3N

Na2S

Step 2:

Namig the compound

1. NaOH.

NaOH is a binary ionic compound containing sodium Na and hydroxyl OH. It therefore a binary compound (i.e it contains two elements). Binary compounds end with - ide.

NaOH is called sodium hydroxide

2. Co3P2. In this case we must determine the oxidation state of Co. This is illustrated below:

Co3P2 = 0

3Co + 2P = 0

3Co + (2x-3) = 0

3Co - 6 = 0

Collect like terms

3Co = 6

Divide both side by 3

Co = 6/3

Co = +2

Co3P2 contains cobalt Co and phosphorus P. It is binary compound and the oxidation state of Co is +2 in the compound. Therefore, the name of Co3P2 is cobalt (II) phosphide

3. Pb(CO3)2. In this case, we must determine the oxidation state of Pb. This is illustrated below:

Pb(CO3)2 = 0

Pb + 2 [ 4 + (-2x3)] = 0

Pb + 2[ 4 - 6] = 0

Pb + 2[-2] = 0

Pb - 4 = 0

Pb = +4

The name of the compound is lead(iv) carbonate or lead(iv) trioxocarbonate (iv)

4. MgF2 is a binary compound containing magnesium Mg and fluorine F. The name therefore is magnesium fluoride

Note: oxidation number of the group 1, 2 and 3 metals are not indicated in their names since their oxidation number is constant.

5. Li2SO3 is a binary ionic compound containing lithium and sulphite. Therefore, the name is lithium sulphite

6. (NH4)3PO4 contain ammonium NH4 and the phosphate. Therefore the name is ammonium phosphate

7. FeO. This is a binary compound, but we must determine the oxidation state of Fe. This is illustrated below:

FeO = 0

Fe + (-2) = 0

Fe - 2 = 0

Fe = +2

Therefore, the name of FeO is iron(II) oxide

8. CaSO4 is binary ionic compound containing calsium and sulphate. It is name as calsium sulphate

9. Ag3N is a binary compound containing silver and nitrogen. It is therefore called silver nitride

10. Na2S is a binary compound containing sodium and sulphur. It is named as sodium sulfide

the correct answer would be d. hope this !