Testbank, Question 027 Which of the following sequences of reagents will move the alcohol functional group from the tertiary position of 1-methylcyclohexanol to a secondary position? A) 1) KOtBu; 2) Hg(OAc)2, H2O; 3) NaBH4 B) 1) TsCl, pyr; 2) KOtBu; 3) BH3·THF; 4) H2O2, NaOH C) 1) H2SO4, heat; 2) BH3·THF; 3) H2O2, NaOH D) 1) TsCl, pyr; 2) NaOH; 3) BH3·THF; 4) H2O2, NaOH C and D will both work

i think its 5049.

i hope this !

answer; capital earns interest; entrepreneurship receives a profit or incurs a loss;

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally