QUESTION 5
A balloon has been filled to a volume of 2.90 L with 0.150 mol of helium gas. If 0.0450 mol of additional helium is added to the balloon while
the temperature and pressure are held constant, what is the new volume of the balloon?
Hint: Avogadro's law is V7/n1=V2/n2

A. 3.95 L
B. 3.77 L
C. 6.54 L
D. 5.45 L

B. 3.77 L is the new volume occupied by the gas.

Explanation:

As per Avogadro's law, which states that if the pressure and temperature held constant, then an equal volume of the gases will occupy an equal number of molecules. It can be written as,

Here, V1, volume of the helium gas = 2.9 L

V2, volume of the additional helium gas in the balloon = ?

n1, moles of helium gas = 0.150 mol

n2, number of moles of additional helium gas = 0.150 + 0.0450 = 0.195 mol

We have to rearrange the equation for V2 as,

V2 =

Now Plugin the values as,

V2 =

  = 3.77 L

So the new volume of the balloon is 3.77 L.

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

a electronegativity decreases beacuse the size of nucleus is bigger.