How many moles of CH3OH are there in 43.7 mL of 0.400 M CH30

The number of moles of CH₃OH present is 0.01748 mole

From the question,

We are to determine the number of moles of CH₃OH that are in 43.7 mL of 0.400 M CH₃OH

Using the formula

Number of moles = Concentration × Volume

From the question

Concentration of CH₃OH = 0.400 M

Volume of CH₃OH = 43.7 mL = 0.0437 L

∴ Number of moles of CH₃OH present = 0.400 × 0.0437

Number of moles of CH₃OH present = 0.01748 mole

Hence, the number of moles of CH₃OH present is 0.01748 mole

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0.0174 mol

Explanation:

Molarity is (moles of solute)/(liters of solvent).  So, to find moles you need to multiply liters by molarity.

0.0437 L × 0.400 M = 0.0174 mol

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