Explain how you linked the predator and its prey to a specific environment.

The mouse and shrew bones were common to all three owls so they were not useful in identifying environments. The gopher bones were unique to the great grey owl of Alaska. Gophers are rodents that are successful in areas with soft soil and lots of grass, so the gopher and this owl would be found in the meadows and evergreen forests of Alaska. The bat was unique to the barking owl of Australia. The bat would be found in woodland habitats where there are many trees the bat can hang from. The gull bones were unique to the short-eared owl of Cuba. Gulls are wetland birds, so the gull and this owl would be found in marshes and coastal areas.  

Explanation: I took it on ed

The mouse and wench bones were regular to each of the three owls so they were not helpful in recognizing conditions. The gopher bones were one of a kind to the incredible dim owl of Alaska. Gophers are rodents that are fruitful in regions with delicate soil and bunches of grass, so the gopher and this owl would be found in the glades and evergreen timberlands of Alaska. The bat was remarkable to the woofing owl of Australia. The bat would be found in forest environments where there are numerous trees the bat can swing from. The gull bones were remarkable to the short-eared owl of Cuba. Gulls are wetland feathered creatures, so the gull and this owl would be found in swamps and waterfront territories.

Explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g