The enthalpy change for the reaction
Cls, graphite) + 1/2O2(g) --> CO(g) cannot be measured directly since some carbon
dioxide is always formed in the reaction.
It can be calculated using Hess's Law and the enthalpy changes of combustion of
graphite and of carbon monoxide.
C(s, graphite) + O2(g) --> CO2 AH=-394 kJmol-1
CO(g) + 1202(8) --> CO2 AH=-283 kJmol-1

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

12 is it do you think so