Sulfuric acid, H2SO4, is a polyprotic acid. More specifically, it is a diprotic acid, meaning that it has the capacity to donate two protons. Write out the two chemical equations for this acid acting as a proton donor in water.

The answer to your question is below

Explanation:

Data

sulfuric acid = H₂SO₄

Proton donors give hydrogens to other molecules most of the time bases or alkalis.

When a molecule donates hydrogen it acquires a negative charge.

First dissociation reaction

                H₂SO₄   +  H₂O  ⇒  HSO₄⁻ + H₃O⁺

Second dissociation reaction

                HSO₄⁻¹ + H₂O ⇒  SO₄⁻²  +  H₃O⁺

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally