Chemistry, 16.04.2020 22:51 genyjoannerubiera
The following reaction was monitored as a function of time: AB→A+BAB→A+B A plot of 1/[AB]1/[AB] versus time yields a straight line with slope 5.2×10−2 (M⋅s)−1(M⋅s)−1 . You may want to reference (Pages 598 - 605) Section 14.5 while completing this problem. Part APart complete What is the value of the rate constant (k)(k) for this reaction at this temperature? Express your answer using two significant figures. kk = 5.2×10−2 M−1s−1M−1s−1 SubmitPrevious Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. A plot of 1/[AB]1/[AB] versus time produces a straight line according to the problem statement. 1[AB]t = kt + 1[AB]o1[AB]t = kt + 1[AB]o The slope of the graph corresponds to the rate constant for this reaction. Part B Write the rate law for the reaction. Write the rate law for the reaction. Rate=kRate=k Rate=k[AB]Rate=k[AB] Rate=k[AB]2Rate=k[AB]2 Rate=k[AB]3Rate=k[AB]3
Answers: 3
Chemistry, 21.06.2019 22:20
Which of the following statements is false regarding aromaticity? a. the compound must be cyclic b. the compound must be fully conjugated c. the compound must be planar d.the number of electrons in the pi system must satisfy the hückel 4n+2 rule e. the compound must have a neutral charge
Answers: 2
The following reaction was monitored as a function of time: AB→A+BAB→A+B A plot of 1/[AB]1/[AB] vers...
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