We shine light of three different wavelengths—325 nm, 455 nm, and 632 nm —on a metal surface. We record the following observations for each wavelength, labeled A, B, and C: Observation A: No photoelectrons were observed. Observation B: Photoelectrons with a kinetic energy of 155 kJ/mol were observed Observation C: Photoelectrons with a kinetic energy of 51 kJ/mol were observed

The correct answer is b) false

Idon’t know what the answer is i wish i could

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.