An 11 M solution containing 449.4 g of ammonium sulfate would contain how many liters?

Answer : The volume of solution will be, 0.309 L

Explanation : Given,

Mass of = 449.4 g

Molar mass of = 132 g/mole

Concentration = 11 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

Now put all the given values in this formula, we get:

Therefore, the volume of solution will be, 0.309 L

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation: