Calculate the molarity of a solution prepared by dissolving 9.8 moles of solid NaOH in enough water to make 3.62 L of solution

2.71mol/L

Explanation:

Step 1:

Data obtained from the question. This includes:

Mole of solute = 9.8 moles

Volume = 3.62L

Molarity = ?

Step 2:

Determination of the molarity.

Molarity is simply the mole of solute per unit litre of the solution. It is represented by the following equation:

Molarity = mole of solute /Volume of solution

Molarity = 9.8 mole / 3.62L

Molarity = 2.71mol/L

A solution of 9.8 moles NaOH in 3.62 L has a molarity of 2.7 M

Explanation:

Step 1: Data given

Number of moles solid NaOH = 9.8 moles

Volume = 3.62 L

Step 2: Calculate molarity of NaOH

Molarity = moles / volume

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 9.8 moles / 3.62 L

Molarity of NaOH solution = 2.7 mol / L = 2.7 M

A solution of 9.8 moles NaOH in 3.62 L has a molarity of 2.7 M

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;