What is the pressure of a mixture of nitrogen (N2) and oxygen (O2) if partial pressure of N2 is 594 mm Hg and the partial pressure of O2 is 165 mm Hg?

The pressure of the mixture containing nitrogen and oxygen is 759 mmHg

From the question given above, the following data were obtained:

Partial pressure of N₂ = 594 mmHg

Partial pressure of O₂ = 165 mm Hg

The pressure of the mixture can be obtained by using the Dalton's law partial pressure as follow:

Total pressure = Partial pressure of N₂ + Partial pressure of O₂

Total pressure = 594 + 165

Therefore, the pressure of the mixture is 759 mmHg

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Total pressure = 759 mmHg

Explanation:

Given data:

Partial pressure of oxygen = 165 mmHg

Partial pressure of nitrogen = 594 mmHg

Total pressure = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ +Pₙ

Total pressure = P(O₂) +  P(N₂)

Total pressure =  165 mmHg + 594 mmHg

Total pressure = 759 mmHg

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally