Suppose you made the intestinal sac too small, and at the end of experiment you could collect only 100 microliters of solution instead of 200 microliters for analysis. You perform the DNS reaction with 100 ul of the recovered solution and 100 ul of water (to bring volume up to 200 ul). How that would affect the concentration of glucose you determined from the standard curve?

Here is the complete part of the question.

Normal Experiment

200 ul solution

200 ul of DNS

400 ul of H2O

A)Half the true concentration

B)Twice the true concentration

C)Equal to the true concentration

B)Twice the true concentration

Explanation:

Since the recovered solution =100ul

Therefore

100ul of DNS will be added.

200ul of H₂⁰ will be added for the experiment.

Although it must be noted that 100ul of H₂⁰ which is half will be added so that the solution will have a strong concentration.

Therefore the result will double the real concentration which indicates an increase in the level of glucose.

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