A gas has a pressure of 0.410 atm and a volume of 32L. At what pressure would the volume of the gas change to 28L?

The new pressure is 0,469 atm

Explanation:

We apply Boyle Mariotte's Law: for a given mass of gas at constant temperature, its pressure and volume vary inversely proportionally (the higher the pressure, the lower the volume and vice versa):

P1 x V1 = P2 xV2               We solve P2:

P2 = (P1 x V1)/V2

P2= (0,410 atm x 32 L) / 28 L

P2= 0,469 atm

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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