A 45mL sample of gas is collected under a pressure of 190 kPa. What will the volume be if the pressure increases to 260 kPa?

The new volume will be 32.88 litres if the pressure increases to 260 kPa.

Explanation:

Data  given:

Initial volume of the gas = 45 ml

initial pressure of the gas = 190 KPa

final pressure on the gas = 260 kpa

final volume =?

from the data provided in the question it is assumed that Boyle's law is used to know the new volume of the gas.

so,

P1V1 = P2V2

Rearranging the equation to determine the final volume of the gas:

V2 =

V2 =

    = 32.88 Litres

the new volume will be 32.88 litres when pressure is increased to 260 Kpa.

i think so it’s will be b yes i believe its

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.