The compound 1,1-difluoroethane decomposes at elevated temperatures to give fluoroethylene and hydrogen fluoride: CH3CHF2(g) → CH2CHF(g) + HF(g) At 460 °C, k = 5.8 × 10-6 s-1 and Ea = 265 kJ/mol. To what temperature (in K) would you have to raise the reaction to make it go four times as fast?

Answer : The final temperature would be, 791.1 K

Explanation :

According to the Arrhenius equation,

or,

where,

= rate constant at =

= rate constant at =

= activation energy for the reaction = 265 kJ/mol = 265000 J/mol

R = gas constant = 8.314 J/mole.K

= initial temperature =

= final temperature = ?

Now put all the given values in this formula, we get:

Therefore, the final temperature would be, 791.1 K

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