What is the concentration of a solution which contains 0.446 g of C6H14N4O2 IN 1.250 L of solution? M

0.0021 M

Explanation:

Given data:

Mass of C₆H₁₄N₄O₂ = 0.446 g

Volume of solution = 1.250 L

Concentration/Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles of solute.

Number of moles = mass/molar mass

Number of moles = 0.446 g/ 174 g/mol

Number of moles = 0.0026 mol

Molarity:

Molarity = 0.0026 mol / 1.250 L

Molarity = 0.0021 M

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o