Consider the following reaction at 298K. Zn2+ (aq) + Co (s) Zn (s) + Co2+ (aq) Which of the following statements are correct? Choose all that apply. K > 1 delta Go < 0 Eocell < 0 The reaction is reactant-favored. n = 4 mol electrons

The reaction is reactant-favored

Explanation:

If we take a look at the reaction equation, Zn2+ (aq) + Co (s) Zn (s) + Co2+ (aq) and consider the reduction potential of the species involved

Zn^2+(aq)/Zn(s)= -0.76

Co^2+(aq)/Co(s)= -0.28

It can easily be seen that the reduction potential of zinc is more negative than that of cobalt. Hence the electrochemical reaction is not spontaneous as written but will greatly favour the reverse reaction.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→