A buffer solution with a pH of 5.28 is prepared with the same volumes of 0.60 M HC2H3O2 and M NaC2H3O2. The Ka of HC2H3O2 is 1.8 ⋅ 10-5.

Molar concentration of [NaC₂H₃O₂]  is 2.08M

Explanation:

It is possible to find pH of the HC₂H₃O₂ / C₂H₃O₂⁻ buffer using H-H equation, thus:

pH = pKa + log₁₀ [C₂H₃O₂⁻] / [HC₂H₃O₂]

Where:

pH = 5.28

pKa is -log Ka: 4.74

[HC₂H₃O₂] = 0.60M -It is possible to use the 0.60M concentration because you will add the same volume of both [HC₂H₃O₂] and [NaC₂H₃O₂] solutions.-

[C₂H₃O₂⁻] = ?

Replacing:

5.28 = 4.74 + log₁₀ [C₂H₃O₂⁻] / [0.60]

0.54 = log₁₀ [C₂H₃O₂⁻] / [0.60]

3.47 =  [C₂H₃O₂⁻] / [0.60]

2.08M = [NaC₂H₃O₂]

Molar concentration of [NaC₂H₃O₂]  is 2.08M

the answer is the first option

explanation:

just googled it m8. not that hard

lol

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.