A monatomic ideal gas expands slowly to twice its original volume, doing 340 JJ of work in the process. Part APart complete Find the heat added to the gas if the process is isothermal. QQ = 340 JJ SubmitPrevious Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. Part B Find the change in internal energy of the gas if the process is isothermal. ΔUΔU = 340 JJ SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C Find the heat added to the gas if the process is adiabatic. QQ = nothing JJ SubmitRequest Answer Part D Find the change in internal energy of the gas if the process is adiabatic. ΔUΔU = nothing JJ SubmitRequest Answer Part E Find the heat added to the gas if the process is isobaric. QQ = nothing JJ SubmitRequest Answer Part F Find the change in internal energy of the gas if the process is isobaric. ΔUΔU = nothing JJ
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For the reaction, 4 a(g) + 3 b(g) => 2 c(g), the following data were obtained at constant temperature. experiment initial[a],mol/l initial [b],mol/l initial rate,m/min 1 0.200 0.150 5.00 2 0.400 0.150 10.0 3 0.200 0.300 10.0 4 0.400 0.300 20.0 which of the following is the correct rate law for the reaction? 1. rate = k[a]2[b]2 2. rate = k[a][b] 3. rate = k[a]2[b] 4. rate = k[a][b]2
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Chemistry, 22.06.2019 14:00
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Chemistry, 22.06.2019 15:00
Areaction is first order with respect to reactant x and second order with respect to reactant y. which statement describes the rate law for this reaction?
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A monatomic ideal gas expands slowly to twice its original volume, doing 340 JJ of work in the proce...
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