A 5.91 g of octane, C8H18, reacts with excess oxygen in a bomb calorimeter. The heat capacity of the calorimeter is 6.97 kJ/°C and the temperature increases by 32.0°C. How much heat, in units of kJ/mol, was absorbed by the bomb calorimeter?

The heat absorbed by the bomb Calorimeter  Q = 5.07

Explanation:

Given data

Heat capacity of calorimeter = 6.97

Temperature Rise ΔT = 32 °c

Therefore the heat absorbed by the bomb calorimeter

 ΔT

Q = 6.97 × 32

Q = 223.04 KJ

Since  1 mole of propane weighs = 44 gm , So

Q = 5.07

Therefore the heat absorbed by the bomb calorimeter  Q = 5.07

explanation:

i think option no d is the correct answer

false

because it does not have the potential to be entirely used up