Determine the new temperature when the volume a gas at 1.56L and 20.0 ˚C changes to 2.02L. Please show work

T₂ = 379.4 K

Explanation:

Given data:

Initial volume = 1.56 L

Initial temperature = 20°C (20+273 = 293 K)

Final volume = 2.02 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂  = V₂T₁ /V₁

T₂ = 2.02 L × 293 K / 1.56 L

T₂ = 591.86 L.K /  1.56 L

T₂ = 379.4 K

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

what is the question here. i think you messed up.