If you have 3x10^23 caffeine molecules, approximately how many miles of caffeine do you have?

0.5 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecules

So, 1 mole of caffeine = 6.02 x 10^23 molecules

Z moles = 3x10^23 molecules

To get the value of Z, cross multiply:

(3 x 10^23 molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)

3 x 10^23 = (6.02 x 10^23 x Z)

Z = (3 x 10^23) ➗ (6.02 x 10^23)

Z = 0.498 moles

[Round 0.498 moles to the nearest tenth as 0.5 moles]

Thus, there are approximately 0.5 moles of caffeine

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

2b2t

explanation:

2b2t