Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.)

1.
3Cl2(g) + 2Fe(s) --> 6Cl-(aq) + 2Fe3+(aq)
Cl2(g)+2e- -->2Cl-(aq) E*= +1.36 V
Fe3+(aq)+3e- -->Fe(s) E*= -0.04 V

2.
Pb(s) + Br2(l) --> Pb2+(aq) + 2Br-(aq)
Pb2+(aq)+2e- -->Pb(s) E*= -0.13 V
Br2(l)+2e- --> 2Br-(aq) E*= +1.07 V

3.
Sn(s) + 2Ag+(aq) --> Sn2+(aq) + 2Ag(s)
Sn2+(aq)+2e- --> Sn(s) E*= -0.14 V
Ag+(aq)+e- --> Ag(s) E*= +0.80 V

The following reaction shows the products when sulfuric acid and aluminum hydroxide react. al(oh)3 + h2so4 → al2(so4)3 + h2o the table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory. sulfuric acid aluminum hydroxide initial amount of reactant 40 g 15 g theoretical yield of water from reactant 14.69 g 10.38 g what is the approximate amount of the leftover reactant? 11.73 g of sulfuric acid 10.33 g of sulfuric acid 11.12 g of aluminum hydroxide 13.67 g of aluminum hydroxide

What is true for a substance that releases energy

How can a give a full method for the experiment of separating sand from water by filtration? 1-materials 2-steps 3-conclusion also for water and salt separated by the evaporation or distillation process