Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O, Hf = –241.82 kJ/mol) according to the equation below. What is the enthalpy of combustion (per mole) of C4H10 (g)? Use .

Enthalpy of combustion (per mole) of is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

Enthalpy of combustion (per mole) of is -2657.5 kJ

h let me think