How much Na2Co3 is needed to produce 35g of Na2Co3?

0.33 moles

Explanation:

Given that,

Amount of moles of Na2CO3 (n) = ?

Mass of Na2CO3 in grams = 35g

For molar mass of Na2CO3, use the molar masses as follows:

Sodium, Na = 23g;

Carbon, C= 12g

Oxygen, O = 16g

Na2CO3 = (23g x 2) + 12g + (16g x 3g)

= 46g + 12g + 48g

= 106g/mol

Since, n = mass in grams / molar mass

n = 35g / 106g/mol

n = 0.33mole

Thus, 0.33 moles of Na2Co3 is needed to produce 35g of Na2Co3

increased stability in the completion of fluorine's outer shell.

it is the most commonly accepted one