A student uses 100 mL of acetic acid. after the experiment the amount of acid is 1200mL with Mallory 1.5 M is formed. What is the molarity of the solution did the student used

18M

Explanation:

Given parameters:

Initial volume of acetic acid  = 100mL

Final volume of solution = 1200mL  = 1.2L

Final molarity  = 1.5M

Unknown:

Initial molarity = ?

Solution:

We might desired a particular concentration of a compound from the stock. This way, we dilute using the right amount of solvent. One critical thing to note is that the number of moles in both solution remains the same.

To solve this problem, let us find the number of moles in the final solution.

  Number of moles in final solution = molarity x volume

                                                           = 1.5 x 1.2

                                                            = 1.8mol

Now original molarity;

          Since    Molarity  =

                         Molarity  =    = 18M

it's filtration, but this is an assumption so my apologies if i got this