What is the molarity of a 500-ml solution containing 340 g of KI

Molarity (M) = 4.09

(Written as 4.09M)

Explanation:

Molarity (M) = mol/L

1st, calculate the number of moles of KI

Molar mass of K = 39.098g per 1 mol

Molar mass of I = 126.9g per 1 mol

39.09+126.9 = 165.99g/mol

Molar mass of KI = 165.99g/mol

Since Molarity (M) is in units of mol/L,

we need to change the given number of 340g of KI to moles.

340g × 1mol/165.99g = 2.05mol KI

Next, convert the given 500ml to Liters

500ml × 1L/1000ml = 0.5L

Lastly, plug these values into the eqaution for Molarity (mol/L)

2.05mol/0.5L = 4.096 M

Molarity (M) = 4.09