PLEASE HELPP
The [H+] of a solution is 1 × 10−2 at 298 K. What is the [OH−] of this solution?
A) 1 × 10−7
B) 1 × 10−2
C) 1 × 10−12
D) 1 × 10−14

Option (C) 1 × 10^−12

Explanation:

Step 1:

Data obtained from the question include:

[H+] = 1x10^−2

[OH−] =?

Step 2:

Determination of [OH−] . This is illustrated below:

[H+] x [OH−] = 1x10^-14

1x10^−2 x [OH−] = 1x10^-14

Divide both side by 1x10^−2

[OH−] = 1x10^-14 / 1x10^−2

[OH−] = 1x10^-12

Therefore, the [OH−] of the solution is 1x10^-12

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explanation:

0.88m hope i am correct : )