The combustion of ethane
(
C
2
H
6
)
produces carbon dioxide and steam.

2
C
2
H
6
(
g
)
+
7
O
2
(
g
)
⟶
4
CO
2
(
g
)
+
6
H
2
O
(
g
)

How many moles of
CO
2
are produced when
5.35
mol
of ethane is burned in an excess of oxygen?

10.7 moles

Explanation:

Step 1:

The balanced equation for the reaction is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Step 2:

Determination of the number of mole of ethane (C2H6) that reacted and the number of mole of CO2 produced from the balanced equation. This is shown below:

From the balanced equation,

Number of mole of C2H6 that reacted = 2 moles

Number of mole of CO2 produced = 4 moles.

Step 3:

Determination of the number of mole of CO2 produced by burning 5.35 mole of ethane (C2H6). This is illustrated below:

From the balanced equation above,

2 moles of C2H6 produced 4 moles of CO2.

Therefore, 5.35 moles of C2H6 will produce = (5.35 x 4)/2 = 10.7 moles of CO2.

From the calculations made above, 10.7 moles of CO2 will be produced when 5.35 moles of ethane (C2H6) is burned in excess oxygen