A different beta blocker is eliminated by a second-order process with a rate constant of 7.6x10-3 min-1. A patient is given 10. mg of the drug. What mass of the drug (in mg) remains in the body 5.0 hours after administration?

Explanation:

A second order process for the elimination (disappearance) of a substance, B, follows the law:

Whose integrated form is:

You are given:

Then, just subsititute and compute:

(notice that the units of k should be mg⁻¹·min⁻¹)

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.