C3H8+5O2 →3CO2+4H2

how many grams of co2 will be produced from 39.0 grams of c3h8 and 11.0 grams of o2?

The answer to your question is 9.075 g of CO₂

Explanation:

Data

mass of C₃H₈ = 39 g

mass of O₂ = 11 g

Balanced  chemical reaction

                C₃H₈  +  5O₂  ⇒  3CO₂  +  4H₂

-Calculate the molar mass of the reactants

C₃H₈ = (12 x 3) + (8 x 1) = 36 + 8 = 44 g

O₂ = (16 x 2) = 32 g

-Calculate the limiting reactant

theoretical yield  C₃H₈ / O₂ = 44/5(32) = 44/ 160 = 0.275

experimental yield C₃H₈/O₂ = 39/11 = 3.5

From the previous result, we conclude that the limiting reactant is O₂ because the experimental yield was higher than the theoretical yield.

-Calculate the mass of CO₂                

             160 g of O₂ 3(44) g of CO₂

               11 g of O₂  x

                    x = (11 x 3(44)) / 160

                    x = 1452 / 160

                    x = 9.075 g of CO₂

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