How many joules are absorbed when 86.8 grams of water is heated from 40.0 degrees C to 86.0 degrees C?
a) 11,400 joules
b) 12,600 joules
c) 14,100 joules
d) 16,700 joules

The answer to your question is the letter d) 16700 joules

Explanation:

Data

mass = m = 86.8 g

temperature 1 = T1 = 40°C

temperature 2 = T2 = 86°C

heat capacity = 4.18 J/g°C

Process

1.- Write the formula to calculate Heat (Q)

        Q = mC(T1 - T2)

2.- Substitution

        Q = (86.8)(4.18)(86 - 40)

3.- Simplification

        Q = (86.8)(4.18)(46)

4.- Result

         Q = 16689.9 Joules ≈ 16700 joules

the volume increases

where are the choice options?