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How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

The answer to your question is 37.5 l of water vapor

Explanation:

Data

volume of ethane = 12.5 l

volume of water vapor = ?

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒   4CO₂  +  6H₂O

-Convert the volume of C₂H₂ to moles

                    1 mol of C₂H₂ 22.4 l

                    x                     12.5 l

                             x = (12.5 x 1) / 22.4

                             x = 0.56 moles

-Calculate the moles of water vapor

                 2 moles of C₂H₂ 6 moles of H₂O

                 0.56 moles of C₂H₂  x

                          x = (0.56 x 6) / 2

                          x = 1.67 moles of H₂O

-Calculate the volume of water vapor

                          22.4 l of H₂O 1 mol

                             x                   1.67 moles

                             x = (1.67 x 22.4) / 1

                             x = 37.5 l

i think the answer is terrae but not 100 percent sure. ▓▬▬ §