Which of the following quantum number combinations is not allowed in an atom?
a. n = 2, l = 1, mr = -1

b. n = 1, l = 1, m = 0

c. n = 8, l = 5, m = -4

d. n = 6, l = 3, m = 2

B. n = 1, l = 1, m = 0

Explanation:

The quantum numbers have the function to locate an electron, so two electrons can't have all the same quantum numbers. There are four:

n - Is the principal quantum number and represents the levels. It varies from 1 to 7, and can be represented by the letters K, L, M, N, O, P, and Q;

l - Is the azimuthal quantum number and represents the sublevels. It varies from 0 to n-1, and can be represented by the letters s, p, d, e, f, g, etc.;

m - Is the magnetic quantum number and represents the orbital. It varies from -l to +l passing by the 0;

ms - Is the spin number, which represents the spin of an electron. It can be +1/2 or -1/2.

In letter B, for n=1, the maximum valor from l is n-1 = 1-1 = 0, then, l = 1 is not possible.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :